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Peter Zijlstra authored
People were complaining about broken balancing with the recent -rt series. A look at /proc/sched_debug yielded: cpu#0, 2393.874 MHz .nr_running : 0 .load : 0 .cpu_load[0] : 177522 .cpu_load[1] : 177522 .cpu_load[2] : 177522 .cpu_load[3] : 177522 .cpu_load[4] : 177522 cpu#1, 2393.874 MHz .nr_running : 4 .load : 4096 .cpu_load[0] : 181618 .cpu_load[1] : 180850 .cpu_load[2] : 180274 .cpu_load[3] : 179938 .cpu_load[4] : 179758 Which indicated the cpu_load computation was hosed, the 177522 value indicates that there is one RT task runnable. Initially I thought the old problem of calculating the cpu_load from a softirq had re-surfaced, however looking at the code shows its being done from scheduler_tick(). [ we really should fix this RT/cfs interaction some day... ] A few trace_printk()s later: sirq-timer/1-19 [001] 174.289744: 19: 50:S ==> [001] 0:140:R <idle> <idle>-0 [001] 174.290724: enqueue_task_rt: adding task: 19/sirq-timer/1 with load: 177522 <idle>-0 [001] 174.290725: 0:140:R + [001] 19: 50:S sirq-timer/1 <idle>-0 [001] 174.290730: scheduler_tick: current load: 177522 <idle>-0 [001] 174.290732: scheduler_tick: current: 0/swapper <idle>-0 [001] 174.290736: 0:140:R ==> [001] 19: 50:R sirq-timer/1 sirq-timer/1-19 [001] 174.290741: dequeue_task_rt: removing task: 19/sirq-timer/1 with load: 177522 sirq-timer/1-19 [001] 174.290743: 19: 50:S ==> [001] 0:140:R <idle> We see that we always raise the timer softirq before doing the load calculation. Avoid this by re-ordering the scheduler_tick() call in update_process_times() to occur before we deal with timers. This lowers the load back to sanity and restores regular load-balancing behaviour. Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl> Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
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