Remove dead code (CID #3)
If (a < 0 || b < 0) is false, then (a >= 0 && b >= 0) is true, which implies (a >= || b >= 0) is true as well. And this was tagged as a FALSE positive!?!
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If (a < 0 || b < 0) is false, then (a >= 0 && b >= 0) is true, which implies (a >= || b >= 0) is true as well. And this was tagged as a FALSE positive!?!