x86: 64 bit print out absent pages num too

so users are not confused with memhole causing big total ram

we don't need to worry about 32 bit, because memhole is always
above max_low_pfn.
Signed-off-by: Yinghai Lu <yinghai@kernel.org>
Signed-off-by: Ingo Molnar <mingo@elte.hu>

arch/x86/mm/init_64.c

@@ -884,6 +884,7 @@ static struct kcore_list kcore_mem, kcore_vmalloc, kcore_kernel,
 void __init mem_init(void)
 {
 	long codesize, reservedpages, datasize, initsize;
+	unsigned long absent_pages;
 
 	start_periodic_check_for_corruption();
 
@@ -899,8 +900,9 @@ void __init mem_init(void)
 #else
 	totalram_pages = free_all_bootmem();
 #endif
-	reservedpages = max_pfn - totalram_pages -
-					absent_pages_in_range(0, max_pfn);
+
+	absent_pages = absent_pages_in_range(0, max_pfn);
+	reservedpages = max_pfn - totalram_pages - absent_pages;
 	after_bootmem = 1;
 
 	codesize =  (unsigned long) &_etext - (unsigned long) &_text;
@@ -917,10 +919,11 @@ void __init mem_init(void)
 				 VSYSCALL_END - VSYSCALL_START);
 
 	printk(KERN_INFO "Memory: %luk/%luk available (%ldk kernel code, "
-				"%ldk reserved, %ldk data, %ldk init)\n",
+			 "%ldk absent, %ldk reserved, %ldk data, %ldk init)\n",
 		(unsigned long) nr_free_pages() << (PAGE_SHIFT-10),
 		max_pfn << (PAGE_SHIFT-10),
 		codesize >> 10,
+		absent_pages << (PAGE_SHIFT-10),
 		reservedpages << (PAGE_SHIFT-10),
 		datasize >> 10,
 		initsize >> 10);