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Li Zefan authored
Each entry in the list has a unique id, so just break out of the loop if the matched id is found. Signed-off-by: Li Zefan <lizf@cn.fujitsu.com> Signed-off-by: David S. Miller <davem@davemloft.net>
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Each entry in the list has a unique id, so just break out of the loop if the matched id is found. Signed-off-by: Li Zefan <lizf@cn.fujitsu.com> Signed-off-by: David S. Miller <davem@davemloft.net>