-
Julia Lawall authored
The of_iounmap is at the out_unmap label, but at that point up has already been freed. The free cannot be moved to the out_unmap label, because that label is reachable from cases where up should not be freed. So the call to of_iounmap is just duplicated, and the goto converted to a return. A simplified version of the semantic match that finds this problem is as follows: (http://coccinelle.lip6.fr/) // <smpl> @@ expression x,e; identifier f; iterator I; statement S; @@ *kfree(x); ... when != &x when != x = e when != I(x,...) S *x->f // </smpl> Signed-off-by: Julia Lawall <julia@diku.dk> Signed-off-by: David S. Miller <davem@davemloft.net>
c4a3987f